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P(0 Copies Prized): P(0 in hand) P(0 in prizes|0 in hand) + P(1 in hand) P(0 in prizes|1 in hand) + P(2 in hand) P(0 in prizes|2 in hand) = dhyper(0,2,58,7) dhyper(0,2,51,6) + dhyper(1,2,58,7) dhyper(0,1,52,6) + dhyper(2,2,58,7) 1 = 0.8084746 P(1 Copy Prized): P(0 in hand) P(1 in prizes|0 in hand) + P(1 in hand) P(1 in prizes|1 in hand) = dhyper(0,2,58,7) dhyper(1,2,51,6) + dhyper(1,2,58,7) dhyper(1,1,52,6) = 0.1830508 P(2 Copies Prized): P(0 in hand) P(2 in prizes|0 in hand) = dhyper(0,2,58,7) dhyper(2,2,51,6) = 0.008474576 Though this does look daunting, keep in mind that we are doing the same thing as before, just with a few more cases
This works because of a special rule where +1/+1 counters and -1/-1 counters cancel each other out
In the Pokmon video game, shes focused on protecting her buddy Cosmog and establishes herself as a main character in the franchise
FIN Magic: The GatheringFINAL FANTASY 109 - Uncommon - English "Hey why don't ya try out that sword I gave you!" Wakka #109 Alchemy, Brawl, Commander, Competitive Brawl, Historic, Legacy, Modern, Pioneer, Standard, Timeless, Vintage Pauper
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